Source code for ddg.math.euclidean

"""Utility functions for Euclidean space.

It includes parametrizations for circles/spheres
in three-dimensional space and an implementation
of Catmull–Rom splines.
"""

import numpy as np
from scipy.spatial.transform import Rotation as rotation

import ddg
from ddg import nonexact

##################################
# Parametrization of Simple Shapes
##################################


[docs]def torus_parametrization(phi, theta, R, r): """ A simple parametrization of the torus Parameters ---------- phi : float the value of the first parameter theta : float the value of the second parameter R : float radius of the larger circle r : float radius of the smaller circle Returns ------- np.ndarray of shape (3, 1) """ return np.array( [ (R + r * np.cos(theta)) * np.cos(phi), (R + r * np.cos(theta)) * np.sin(phi), r * np.sin(theta), ] )
[docs]def mobius_strip_parametrization(u, v, R): """ A simple parametrization of the moebius strip Parameters ---------- u : float the value of the first parameter v : float the value of the second parameter R : float radius of the midcircle of the moebius strip Returns ------- np.ndarray of shape (3, 1) """ return np.array( [ (R + (v / 2) * np.cos(u / 2)) * np.cos(u), (R + (v / 2) * np.cos(u / 2)) * np.sin(u), (v / 2) * np.sin(u / 2), ] )
############################## # Utilities for quadrilaterals ##############################
[docs]def intersect_diags(v1, v2, v3, v4): r""" For a quadrilateral(v1,v2,v3,v4) that lies in a plane, get the intersection point of the diagonals. The four points are given as an argument in positive cyclic order. :: v4-----v3 |\ /| | x | |/ \| v1-----v2 Parameters ---------- v1, v2, v3, v4 : numpy.ndarray of shape (n,) Four points of quadrilateral vertices in positive cyclic order. Returns ------- numpy.ndarray of shape (n,) Notes ----- Works for arbitrarily many dimensions as long as it is contained in a plane. """ v1, v2, v3, v4 = map(np.array, [v1, v2, v3, v4]) m = np.array([v2 - v1, v3 - v1, v4 - v1]) # assert np.linalg.matrix_rank(m) <= 2, "Points are not contained in a plane" A = np.transpose(np.array([v3 - v1, v4 - v2])) t = np.linalg.lstsq(A, v2 - v1, rcond=None)[0][0] return v1 + t * (v3 - v1)
[docs]def intersect_edges(v1, v2, v3, v4): r""" For a quadrilateral (v1,v2,v3,v4) that lies in a plane, get the intersection of the two opposite edges (v1,v2) and (v3,v4). :: v4-----v3-- | | \ | | x | | / v1-----v2-- Parameters ---------- v1, v2, v3, v4 : numpy.ndarray of shape (n,) Four points of quadrilateral vertices in positive cyclic order. Returns ------- numpy.ndarray of shape (n,) Notes ----- Works for arbitrarily many dimensions as long as it is contained in a plane. """ v1, v2, v3, v4 = map(np.array, [v1, v2, v3, v4]) m = np.array([v3 - v4, v2 - v1]) assert np.linalg.matrix_rank(m) != 1, "Opposite edges are parallel" m = np.array([v2 - v1, v3 - v1, v4 - v1]) assert np.linalg.matrix_rank(m) <= 2, "Points are not contained in a plane" A = np.transpose(np.array([v2 - v1, v3 - v4])) t = np.linalg.lstsq(A, v4 - v1, rcond=None)[0][0] return v1 + t * (v2 - v1)
[docs]def christoffel_dual_quad(v1, v2, v3, v4): """ A Christoffel dual quadrilateral of the given quadrilateral. Corresponding edges and non-corresponding diagonals are parallel. This determines the dual quadrilateral up to scaling. Parameters ---------- v1, v2, v3, v4 : numpy.ndarray of shape (n,) Coordinates of the given quadrilateral. Returns ------- V1, V2, V3, V4 : numpy.ndarray of shape (n,) Coordinates of the dual quadrilateral. """ v1, v2, v3, v4 = map(np.array, [v1, v2, v3, v4]) m = intersect_diags(v1, v2, v3, v4) alpha = np.linalg.norm(v1 - m) beta = np.linalg.norm(v2 - m) gamma = np.linalg.norm(v3 - m) delta = np.linalg.norm(v4 - m) if np.dot(v3 - m, v1 - m) < 0: alpha = -alpha if np.dot(v2 - m, v4 - m) < 0: delta = -delta V1 = np.zeros(v1.size) V2 = (v2 - v1) / (alpha * beta) V3 = V2 + (v3 - v2) / (beta * gamma) V4 = (v4 - v1) / (alpha * delta) return (V1, V2, V3, V4)
[docs]def focal_points(v1, v2, v3, v4): r""" For a quadrilateral (v1, v2, v3, v4), get the focal points of the quadrilateral. These are the intersecting points of all edges. :: p2 / \ / \ v4-----v3-- | | \ | | p1 | | / v1-----v2-- Parameters ---------- v1, v2, v3, v4 : numpy.ndarray of shape (n,) Coordinates of the given quadrilateral. Returns ------- p1, p2 : numpy.ndarray of shape (n,) Focal points of the given quadrilateral. """ v1, v2, v3, v4 = map(np.array, [v1, v2, v3, v4]) p1 = intersect_edges(v1, v2, v3, v4) p2 = intersect_edges(v2, v3, v4, v1) return (p1, p2)
[docs]def diagonal_triangle(v1, v2, v3, v4): r""" For a quadrilateral (v1, v2, v3, v4), get the diagonal triangle of the quadrilateral. These points determine the triangle formed by the intersection of all diagonals. :: p3 / \ / \ v4-----v3-- |\ /| \ | p1 | p2 |/ \| / v1-----v2-- Parameters ---------- v1, v2, v3, v4 : numpy.ndarray of shape (n,) Coordinates of the given quadrilateral. Returns ------- p1, p2, p3 : numpy.ndarray of shape (n,) Diagonal triangle of the given quadrilateral. """ v1, v2, v3, v4 = map(np.array, [v1, v2, v3, v4]) p1 = intersect_diags(v1, v2, v3, v4) p2, p3 = focal_points(v1, v2, v3, v4) return (p1, p2, p3)
########################################################## # Utilities for spheres/circles and their parametrizations ##########################################################
[docs]def circle_fct(t, center, radius=1, normals=None): """ Parametrization map of a circle with a given center, radius and list of normals. The dimensions of the normals must match the dimension of the center and both must be >= 2. Parameters ---------- t: float Parameter for the parametrization. center: numpy.ndarray of shape (d,) Center of the circle. normals: numpy.ndarray of shape (n,d) (default=None) Normals of the circle that determine the orthogonal complement of the subspace containing the circle. If None are given the orthogonal complement will be determined by the dimension of the center and its normals consist of unit normal vectors. These vectors must be linearly independent(!) radius: float (default=1) Radius of the circle. Returns ------- float Value of a point on the circle at parameter t. """ center = np.array(center) dim = center.shape[0] if normals is None: normals = [ddg.math.linalg.e(i, dim) for i in range(2, dim)] elif np.ndim(normals) == 1: normals = np.array([normals]) if not len(normals) < dim - 1: raise ValueError( "The number of normals must be smaller than the dimension of the " "circle center minus 2. The given circle center has dimension " f"{dim} but {len(normals)} normals were given." ) v = np.concatenate((np.zeros(dim - 2), [np.cos(t), np.sin(t)])) v *= radius if dim > 2: if np.shape(normals)[1] != dim: raise ValueError( "Shapes of center and normal mismatch. The center has " f"dimension {dim} and the normals have shape " f"{np.shape(normals)}, which should be (*, {dim})." ) rot = extend_to_onb(normals, index=0) v = rot @ v return v + center
[docs]def sphere_fct(u, v, center=None, radius=1): """ Parameterization map of a 2d sphere in 3d euclidean space with a given center and radius Parameters ---------- u: float First parameter for the parametrization. v: float Second parameter for the parametrization. radius: float (default=1) Radius of the sphere. center: numpy.ndarray of shape (3,) (default=np.array([0, 0, 0])) Center of the sphere. Returns ------- float Value of the sphere parametrization for given parameters u and v. """ center = np.array([0, 0, 0]) if center is None else center if len(center) != 3: raise ValueError( "The center for the sphere must be 3 dimensional. A" f" {len(center)} dimensional ndarray was given: {center}." ) x1 = radius * np.cos(u) * np.sin(v) + center[0] x2 = radius * np.sin(u) * np.sin(v) + center[1] x3 = radius * np.cos(v) + center[2] return np.array([x1, x2, x3])
[docs]def circumcenter(v0, v1, v2): """ Computes the center of the circle through the three given points in two-dimensional or three-dimensional space. Parameters ---------- v0 : tuple of float or numpy.ndarray of shape either (2,) or (3,) First vertex v1 : tuple of float or numpy.ndarray of shape either (2,) or (3,) Second vertex v2 : tuple of float or numpy.ndarray of shape either (2,) or (3,) Third vertex Returns ------- numpy.ndarray of shape (2,) or (3,) Center of the circle through the points v0, v1, v2 """ v0, v1, v2 = np.array(v0), np.array(v1), np.array(v2) ec1 = v1 - v0 ec2 = v2 - v1 ec3 = v0 - v2 alpha = ( np.linalg.norm(ec2) ** 2 * (-1) * np.dot(ec1, ec3) / (2 * np.linalg.norm(np.cross(ec1, ec2)) ** 2) ) beta = ( np.linalg.norm(ec3) ** 2 * (-1) * np.dot(ec1, ec2) / (2 * np.linalg.norm(np.cross(ec1, ec2)) ** 2) ) gamma = ( np.linalg.norm(ec1) ** 2 * (-1) * np.dot(ec2, ec3) / (2 * np.linalg.norm(np.cross(ec1, ec2)) ** 2) ) ac1 = alpha * v0 bc2 = beta * v1 gc3 = gamma * v2 return ac1 + bc2 + gc3
[docs]def circle_through_three_points(v0, v1, v2, atol=None, rtol=None): """ Computes the center, radius and normal of the circle through the three given points in three-dimensional space. Parameters ---------- v0 : tuple of float or numpy.ndarray of shape (3,) First vertex v1 : tuple of float or numpy.ndarray of shape (3,) Second vertex v2 : tuple of float or numpy.ndarray of shape (3,) Third vertex atol, rtol : float (default=None) If None, the global defaults will be used. Returns ------- numpy.ndarray of shape (3,), float, numpy.ndarray of shape (3,) Center, radius, normal of the circle through the three given points, respectively. Raises ------ ValueError If the three points given lie on a common line Notes ----- Since the cross product of difference vectors of the points is computed, their dimension must be three. If 2d points are given instead, the third component is assumed to be zero and the normal is returned as a value (type float), such that the normal vector is given by [0, 0, normal] """ v0, v1, v2 = np.array(v0), np.array(v1), np.array(v2) n = np.cross((v1 - v0), (v2 - v0)) if not nonexact.allclose(n, 0.0, atol=atol, rtol=rtol): n = n / np.linalg.norm(n) else: raise ValueError("Not a possible circle. The three points given are colinear!") cc = circumcenter(v0, v1, v2) return cc, np.linalg.norm(cc - v0), n
[docs]def sphere_through_four_points(p0, p1, p2, p3): """ Computes the center and radius of sphere through the four given points in three-dimensional space. Parameters ---------- p0 : tuple of float or numpy.ndarray of shape (3,) First point p1 : tuple of float or numpy.ndarray of shape (3,) Second point p2 : tuple of float or numpy.ndarray of shape (3,) Third point p3 : tuple of float or numpy.ndarray of shape (3,) Fourth point Returns ------- numpy.ndarray of shape (3,), float Center, radius of the sphere respectively. """ points = [np.array(p0), np.array(p1), np.array(p2), np.array(p3)] A = [embed(p, level=1, index=0) for p in points] b = [-np.linalg.norm(p) ** 2 for p in points] x = np.linalg.solve(A, b) xm = -x[1] / 2 ym = -x[2] / 2 zm = -x[3] / 2 r2 = xm**2 + ym**2 + zm**2 - x[0] return [xm, ym, zm], np.sqrt(r2)
########################################## # Utilities for 2D and 3D transformations ##########################################
[docs]def rotation_2d(alpha): """ Returns 2x2 rotation matrix :: cos(alpha) | -sin(alpha) A = ------------------------ sin(alpha) | cos(alpha) Parameters ---------- alpha : float Rotation angle Returns ------- numpy.ndarray of shape (2, 2) """ return np.array([[np.cos(alpha), -np.sin(alpha)], [np.sin(alpha), np.cos(alpha)]])
[docs]def rotation_from_to(source, target, homogeneous=True, atol=None, rtol=None): """ Returns a 3x3 rotation matrix taking the source vector to the target vector, or a 4x4 matrix of the type :: A | 0 T = ----- 0 | 1 Parameters ---------- source : tuple of float or numpy.ndarray of shape (3,) Source vector target : tuple of float or numpy.ndarray of shape (3,) Target vector homogeneous: bool, (default=True) Determines whether 4x4 matrix or 3x3 matrix is returned atol, rtol : float (default=None) If None, the global defaults will be used. Returns ------- numpy.ndarray of shape either (3, 3) or (4, 4) Rotation matrix taking source vector to target vector Raises ------ ValueError If at least one of the vectors is the zero vector (0, 0, 0) Notes ----- If source and target are parallel the identety matirx is returned. If source and target are anti-parallel a correspoding 180 degree rotation is returned. """ if nonexact.allclose(source, 0.0, atol=atol, rtol=rtol) or nonexact.allclose( target, 0.0, atol=atol, rtol=rtol ): raise ValueError("Source or target is too close to the zero vector.") norm_source = np.linalg.norm(source) norm_target = np.linalg.norm(target) unit_source = source / norm_source unit_target = target / norm_target d = np.dot(unit_source, unit_target) c = np.cross(unit_source, unit_target) if ( nonexact.allclose(c, 0.0, atol=atol, rtol=rtol) and d < 0 ): # source and target are anti-parallel # choose some orthogonal axis a = ddg.math.inner_product.get_row_complement(np.array([source]))[0] # 180 degree rotation around this axis T = np.identity(3) + 2 * np.linalg.matrix_power(skew_symmetric_matrix(a), 2) else: # rotation matrix around c, mapping source to target T = ( np.identity(3) + skew_symmetric_matrix(c) + (1 / (1 + d)) * np.linalg.matrix_power(skew_symmetric_matrix(c), 2) ) if homogeneous: T = np.insert(T, 3, np.zeros(3), axis=1) T = np.insert(T, 3, np.array([0, 0, 0, 1]), axis=0) return T
[docs]def scale_rotation_from_to(source, target, homogeneous=True, atol=None, rtol=None): """ Returns a 3x3 scale rotation matrix taking the source vector to the target vector, or a 4x4 matrix of the type :: A | 0 T = ----- 0 | 1 Parameters ---------- source : tuple of float or numpy.ndarray of shape (3,) Source vector target : tuple of float or numpy.ndarray of shape (3,) Target vector homogeneous: bool, (default=True) Determines whether 4x4 matrix or 3x3 matrix is returned atol, rtol : float (default=None) If None, the global defaults will be used. Returns ------- numpy.ndarray of shape either (3, 3) or (4, 4) Scale rotation matrix taking source vector to target vector Raises ------ ValueError If at least one of the vectors is the zero vector (0, 0, 0) """ T = rotation_from_to(source, target, homogeneous=homogeneous, atol=atol, rtol=rtol) norm_source = np.linalg.norm(source) norm_target = np.linalg.norm(target) T = ( scaleXYZ(np.full(3, norm_target), homogeneous=homogeneous)
[docs] @ T @ scaleXYZ(np.full(3, 1 / norm_source), homogeneous=homogeneous) ) return T
def rotation_angle_axis(rotation_vector, homogeneous=True): """ This function parameterizes rotation using axis–angle representation. It returns either 4x4 matrix of the type :: A | 0 M = ----- 0 | 1 where A represents the rotation matrix or A as a 3x3 rotation matrix. Parameters ---------- rotation_vector : tuple of float or numpy.ndarray of shape (3,) A 3-dimensional vector which is co-directional to the axis of rotation and whose norm gives the angle of rotation homogeneous: bool, (default=True) Determines whether 4x4 matrix or 3x3 matrix is returned Returns ------- numpy.ndarray of shape either (3, 3) or (4, 4) """ T = rotation.from_rotvec(rotation_vector).as_matrix() if homogeneous: T = np.insert(T, 3, np.zeros(3), axis=1) T = np.insert(T, 3, np.array([0, 0, 0, 1]), axis=0) return T
[docs]def scaleXYZ(xyz=(1, 1, 1), homogeneous=True): """ Returns either 4x4 matrix of type :: A | 0 M = ----- 0 | 1 where A denotes diagonal scaling matrix, or A as 3x3 diagonal scaling matrix Parameters ---------- xyz : tuple of float or numpy.ndarray of shape (3,), (default=(1, 1, 1)) Scaling factors in x, y and z directions homogeneous: bool, (default=True) Determines whether 4x4 matrix or 3x3 matrix is returned Returns ------- numpy.ndarray of shape either (3, 3) or (4, 4) Scaling matrix in either affine or homogeneous coordinates """ if homogeneous: xyz = np.append(np.array(xyz), 1) return np.diag(np.array(xyz))
[docs]def translation_to(b=(0, 0, 0)): """ Returns 4x4 matrix of type :: I | b M = ----- 0 | 1 where I denotes 3x3 identity matrix and b denotes 3x1 translation vector Parameters ---------- b : tuple of float or numpy.ndarray of shape (3,), (default=(0, 0, 0)) Translation vector Returns ------- numpy.ndarray of shape (4, 4) """ T = np.eye(4) T[:3, 3] = b return T
[docs]def reflection_in_a_hyperplane(normal, level): """Calculate the reflection matrix (in homogeneous coordinates) of a hyperplane. Parameters ---------- normal : array_like of shape (n,) Normal of the plane level : float Level of the plane Returns ------- reflection_matrix : np.ndarray of shape (n + 1, n + 1) Raises ------ ValueError If the given normal does not have shape (n,). Examples -------- >>> import numpy as np >>> from ddg.math.euclidean import reflection_in_a_hyperplane as re >>> M = re((1, 0), 0) >>> M array([[-1., 0., 0.], [ 0., 1., 0.], [ 0., 0., 1.]]) >>> p = (-5, 10, 1) >>> reflected_p = M.dot(p) >>> reflected_p array([ 5., 10., 1.]) >>> M = re((1, 1, 1), 5) >>> M array([[ 0.33333333, -0.66666667, -0.66666667, 5.77350269], [-0.66666667, 0.33333333, -0.66666667, 5.77350269], [-0.66666667, -0.66666667, 0.33333333, 5.77350269], [ 0. , 0. , 0. , 1. ]]) >>> p = (0, 0, 0, 1) >>> reflected_p = M.dot(p) >>> reflected_p array([5.77350269, 5.77350269, 5.77350269, 1. ]) """ n = normalize(normal) if n.ndim != 1: raise ValueError("The given normal is not a vector.") dim = n.shape[0] sub_matrix = np.eye(dim, dim) - 2 * np.outer(n, n.T) inner_matrix = np.insert(sub_matrix, dim, 2 * level * n, axis=1) reflection_matrix = np.insert( inner_matrix, dim, np.append(np.zeros(dim), 1), axis=0 ) return reflection_matrix
##################### # Catmull–Rom Spline #####################
[docs]def catmull_rom_spline(P0, P1, P2, P3, alpha=0.5, nPoints=100): """ Computes the points of the Catmull-Rom spline segment, using four control points. Parameters ---------- P0 : numpy.ndarray of shape either (2,) or (3,) First control point, which is used to determine curvature of spline segment between P1 and P2 P1 : numpy.ndarray of shape either (2,) or (3,) Second control point, which forms one end of the spline segment P2 : numpy.ndarray of shape either (2,) or (3,) Third control point, which forms the other end of the spline segment P3 : numpy.ndarray of shape either (2,) or (3,) Fourth control point, which is used to determine curvature of spline segment between P1 and P2 alpha : float (default=0.5) Spline Knot parameter, ranges from 0 to 1 nPoints : int (default=100) Number of points making up the resulting spline segment Returns ------- numpy.ndarray of shape either (nPoints, 2) or (nPoints, 3) The Catmull-Rom spline segment between points P1 and P2 Notes ----- Depending on the value of alpha, we get uniform (alpha=0), centripetal (alpha=0.5) and chordal (alpha=1) parameterization of Catmull–Rom spline. """ P0, P1, P2, P3 = map(np.array, [P0, P1, P2, P3]) # Calculate t0 to t3 def tj(ti, Pi, Pj): return (np.linalg.norm(Pi - Pj)) ** alpha + ti t0 = 0 t1 = tj(t0, P0, P1) t2 = tj(t1, P1, P2) t3 = tj(t2, P2, P3) # Only calculate points between P1 and P2 t = np.linspace(t1, t2, nPoints) # Reshape so that we can multiply by the points P0 to P3 # and get a point for each value of t. t = t.reshape(len(t), 1) A1 = (t1 - t) / (t1 - t0) * P0 + (t - t0) / (t1 - t0) * P1 A2 = (t2 - t) / (t2 - t1) * P1 + (t - t1) / (t2 - t1) * P2 A3 = (t3 - t) / (t3 - t2) * P2 + (t - t2) / (t3 - t2) * P3 B1 = (t2 - t) / (t2 - t0) * A1 + (t - t0) / (t2 - t0) * A2 B2 = (t3 - t) / (t3 - t1) * A2 + (t - t1) / (t3 - t1) * A3 C = (t2 - t) / (t2 - t1) * B1 + (t - t1) / (t2 - t1) * B2 return C
[docs]def catmull_rom_curve(P, alpha=0.5, nPoints=4): """ Calculate Catmull Rom for a chain of points and return the combined curve. Parameters ---------- P : list of numpy.ndarray, each of shape (2,) or (3,) Chain of points from which the quadruples for the catmull_rom_spline function are taken alpha : float (default=0.5) Spline Knot parameter, ranges from 0 to 1 nPoints : int (default=4) The number of points to include in each curve segment Returns ------- numpy.ndarray of shape either (m, 2) or (m, 3) Catmull-Rom curve made up of n-1 spline segments, each containing nPoints, i.e m = 2 - n + nPoints*(n-1) where n denotes the length of given list of points Notes ----- The resulting curve passes through all the given points. The centripetal parameterization (alpha=0.5) of Catmull-Rom curve is the only parameterization that guarantees that the curves do not form cusps or self-intersections within its segments. """ size = len(P) C = [] for i in range(size - 1): if i == 0: c = catmull_rom_spline(2 * P[0] - P[1], P[0], P[1], P[2], alpha, nPoints) C.extend(c) elif i == size - 2: c = catmull_rom_spline( P[size - 3], P[size - 2], P[size - 1], 2 * P[size - 1] - P[size - 2], alpha, nPoints, ) C.extend(c[1:]) else: c = catmull_rom_spline(P[i - 1], P[i], P[i + 1], P[i + 2], alpha, nPoints) C.extend(c[1:]) return np.array(C)
########################## # Other utility functions ##########################
[docs]def extend_to_onb(vectors, index=0): """ Extends a given list of vectors to an orthonormal basis for n-dimensional space. Parameters ---------- vectors : list of numpy.ndarray of shape (n,) or a numpy.ndarray of shape (k, n) List of linearly independent vectors to complete into an orthonormal basis. index : int (default=0) If only one vector is given, it's possible to specify its index in the resulting orthonormal basis. If more than one vector is given, the first k columns of the result will have the same span as the given family of vectors. Returns ------- numpy.ndarray of shape (n, n) Columns of resulting matrix form an orthonormal basis. Raises ------ ValueError If vectors are given as numpy.ndarray of dimension greater than 2. ValueError If the given family of vectors is linearly dependent. Notes ----- The given vector(s) will be normalized. This function uses Gram-Schmidt, so it might be a bit unstable. If the vectors are given as a 2-dimensional numpy.ndarray, the rows of the matrix will be considered as input. """ vectors = np.array(vectors) if vectors.ndim not in [1, 2]: raise ValueError( f"Can not extend a {vectors.ndim}-dimensional " "numpy array to an orthonormal basis." ) if vectors.ndim == 1: vectors = [vectors] if np.linalg.matrix_rank(vectors) != len(vectors): raise ValueError("The given family of vectors is linearly dependent.") n = vectors[0].shape[0] k = len(vectors) onb = np.zeros((n, n)) onb.T[0] = vectors[0] / np.linalg.norm(vectors[0]) for i in range(1, k): v = vectors[i] u = onb.T[i - 1] proj = np.dot(u, v) / np.dot(u, u) tmp = v - proj * u onb.T[i] = tmp / np.linalg.norm(tmp) if k != n: eye = np.eye(n) for i in range(k, n): temp = eye - onb @ onb.T j = np.where(sum(nonexact.isclose(temp, 0)) < n)[0][0] onb.T[i] = temp.T[j] / np.linalg.norm(temp.T[j]) if len(vectors) == 1 and index != 0: onb[:, [0, index]] = onb[:, [index, 0]] return onb
[docs]def distance(p0, p1): """ Computes the Euclidean distance between two given point in n-dimensional space. Parameters ---------- p0 : tuple of float or numpy.ndarray of shape (n,) First point p1 : tuple of float or numpy.ndarray of shape (n,) Second point Returns ------- float Euclidean distance, i.e l2 norm of difference between the given two point """ diff = np.subtract(np.array(p0), np.array(p1)) return np.linalg.norm(diff)
[docs]def distance_lines(a, v, b, w): """ Calculate the shortest distance between the lines a + sv and b + tw. This only works in 3D-space. Parameters ---------- a, b : numpy.ndarray of shape (3,) Initial vector of line v, w : numpy.ndarray of shape (3,) Direction vector of line Returns ------- float Shortest distance of line. """ n = np.cross(v, w) n = n / np.linalg.norm(n) return np.abs(np.dot(n, b - a))
[docs]def skew_symmetric_matrix(v): """ Returns the skew-symmetric matrix :: 0 | -v3 | v2 ----+------+---- v3 | 0 | -v1 ----+------+---- -v2 | v1 | 0 Parameters ---------- v : numpy.ndarray of shape (3,) Returns ------- numpy.ndarray of shape (3, 3) """ return np.array([[0, -v[2], v[1]], [v[2], 0, -v[0]], [-v[1], v[0], 0]])
[docs]def normalize(v): """ Normalizes a given vector in n-dimensional space. Parameters ---------- v : tuple of float or numpy.ndarray of shape (n,) The vector to normalize Returns ------- numpy.ndarray of shape (n,) The normalized vector if it is non-zero, the zero vector otherwise """ vector = np.array(v) if not all(vector == 0): return vector / np.linalg.norm(vector) else: return vector
[docs]def embed(v, level=0, index=-1): """Embeds a coordinate vector by inserting the given level. Parameters ---------- vector : tuple of float or numpy.ndarray of shape (n,) The vector to be embedded level : float (default=0) The value to insert i : int (default=-1) Index of inserted value in the output Returns ------- numpy.ndarray of shape (n+1,) """ i = index vector = np.array(v) if -np.size(vector) <= i <= -1: i += np.size(vector) + 1 return np.insert(vector, i, level)
[docs]def angle_bisector_orientation_preserving(n1, d1, n2, d2): """Calculate the orientation preserving angle bisector of two hyperplanes. The hyperplanes are represented by a n-dimensional normal vector and a level. Parameters ---------- n1 : array_like of shape (n,) Normal of first hyperplane. d1 : float Level of first hyperplane (distace to origin). n2 : array_like of shape (n,) Normal of second hyperplane. d2 : float Level of second hyperplane (distace to origin). Returns ------- n, d : numpy.ndarray of shape (n,), float Normal and level of orientation preserving angle bisector. """ n1_normed = normalize(n1) n2_normed = normalize(n2) n = n1_normed + n2_normed n_norm = np.linalg.norm(n) d = d1 + d2 return n / n_norm, d / n_norm
[docs]def angle_bisector_orientation_reversing(n1, d1, n2, d2): """Calculate the orientation reversing angle bisector of two hyperplanes. The hyperplanes are represented by a n-dimensional normal vector and a level. Parameters ---------- n1 : array_like of shape (n,) Normal of first hyperplane. d1 : float Level of first hyperplane (distace to origin). n2 : array_like of shape (n,) Normal of second hyperplane. d2 : float Level of second hyperplane (distace to origin). Returns ------- n, d : numpy.ndarray of shape (n,), float Normal and level of orientation reversing angle bisector. """ n1_normed = normalize(n1) n2_normed = normalize(n2) n = n1_normed - n2_normed n_norm = np.linalg.norm(n) d = d1 - d2 return n / n_norm, d / n_norm